Base | Representation |
---|---|

bin | 1111011100001101101… |

… | …01010111101111110101 |

3 | 1212201102110110201200101 |

4 | 13232012311113233311 |

5 | 32143023014142003 |

6 | 1043421140114101 |

7 | 53221232033524 |

oct | 7560665275765 |

9 | 1781373421611 |

10 | 530543115253 |

11 | 195002837008 |

12 | 869a5995931 |

13 | 3b050bb2738 |

14 | 1b96d8484bb |

15 | dc0229011d |

hex | 7b86d57bf5 |

530543115253 has 8 divisors (see below), whose sum is σ = 546045641280. Its totient is φ = 515263647360.

The previous prime is 530543115233. The next prime is 530543115293. The reversal of 530543115253 is 352511345035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^{k}-530543115253 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530543115233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55759708 + ... + 55769221.

It is an arithmetic number, because the mean of its divisors is an integer number (68255705160).

Almost surely, 2^{530543115253} is an apocalyptic number.

It is an amenable number.

530543115253 is a deficient number, since it is larger than the sum of its proper divisors (15502526027).

530543115253 is a wasteful number, since it uses less digits than its factorization.

530543115253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111529067.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 530543115253 in words is "five hundred thirty billion, five hundred forty-three million, one hundred fifteen thousand, two hundred fifty-three".

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